28x^2=441

Solution for 28x^2=441 equation:

28x^2=441

We move all terms to the left:

28x^2-(441)=0

a = 28; b = 0; c = -441;
Δ = b2-4ac
Δ = 02-4·28·(-441)
Δ = 49392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{49392}=\sqrt{7056*7}=\sqrt{7056}*\sqrt{7}=84\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84\sqrt{7}}{2*28}=\frac{0-84\sqrt{7}}{56}
=-\frac{84\sqrt{7}}{56}
=-\frac{3\sqrt{7}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84\sqrt{7}}{2*28}=\frac{0+84\sqrt{7}}{56}
=\frac{84\sqrt{7}}{56}
=\frac{3\sqrt{7}}{2}
$